[3a - a (2 - a)] - a
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[ 3a - a( 2 - a ) ] - a
=> [ 3a - 2a + a² ] - a
=> a + a² - a
=> a²
=> [ 3a - 2a + a² ] - a
=> a + a² - a
=> a²
Answered by
1
It is given that ,
[ 3a - a ( 2 - a ) ] - a
= [ 3a - ( 2a - a² ) ] - a
= [ 3a - 2a + a² ] - a
= ( a + a² ) - a
= a + a² - a
= a²
••••
[ 3a - a ( 2 - a ) ] - a
= [ 3a - ( 2a - a² ) ] - a
= [ 3a - 2a + a² ] - a
= ( a + a² ) - a
= a + a² - a
= a²
••••
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