[3y - (x + 2y)] - [x + (2x - y)]
Answers
Answered by
3
=>
3y-x-2y-x-2x+y
=>
(3y-2y+y)-x-2x-x
=>
2y-4x ans.
3y-x-2y-x-2x+y
=>
(3y-2y+y)-x-2x-x
=>
2y-4x ans.
Answered by
0
It is given that ,
[ 3y - ( x + 2y ) ] - [ x + ( 2x - y ) ]
= [ 3y - x - 2y ] - [ x + 2x - y ]
= [ y - x ] - [ 3x - y ]
= y - x - 3x + y
= y + y - x - 3x
= 2y - 4x
••••
[ 3y - ( x + 2y ) ] - [ x + ( 2x - y ) ]
= [ 3y - x - 2y ] - [ x + 2x - y ]
= [ y - x ] - [ 3x - y ]
= y - x - 3x + y
= y + y - x - 3x
= 2y - 4x
••••
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