Question

3a) Calculate the number of moles
present in 9 g of ethane.​

Answer 1

Answer:

0.3 moles of ethane are present in 9g of ethane

Explanation:

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Answer 2

Answer:

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Explanation:

Mass of the Ethane = 9 g.

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6 .: Molar mass of the ethane = 12 x 2 + %3D 6 = 24 + 6 30 *

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6 .: Molar mass of the ethane = 12 x 2 + %3D 6 = 24 + 6 30 * No. of moles = Mass/Molar mass %3D

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6 .: Molar mass of the ethane = 12 x 2 + %3D 6 = 24 + 6 30 * No. of moles = Mass/Molar mass %3D .: No. of moles of the Ethane = 9/30 = 3/10 = 0.3 moles.

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6 .: Molar mass of the ethane = 12 x 2 + %3D 6 = 24 + 6 30 * No. of moles = Mass/Molar mass %3D .: No. of moles of the Ethane = 9/30 = 3/10 = 0.3 moles. Hence, the number of the moles in 9 g of the Ethane is 0.3 moles.

Mass of the Ethane = 9 g. Chemical Formula of the Ethane = C2H6 .: Molar mass of the ethane = 12 x 2 + %3D 6 = 24 + 6 30 * No. of moles = Mass/Molar mass %3D .: No. of moles of the Ethane = 9/30 = 3/10 = 0.3 moles. Hence, the number of the moles in 9 g of the Ethane is 0.3 moles. Hope it helps.

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