Question

3a²=2(a+4) solve by quadratic formula​

Answer 1

Step-by-step explanation:

3a²=2a+4

3a²-2a-4=0

it is in the form ax²+bx+c=0

here a=3, b=-2 and c=-4

x=-b±root of (b²-4ac) whole divided by 2a

x=-(-2)±root of [(-2)²-4(3)(-4)] whole divided by 2(3)

=2±root of (4+48) whole divided by 6

=(2±√52)/6

=[2±√4(13)]/6

=[2±2√13]/6

=2/6[1±√13]

=1/3(1±√13)