(3a²)(-2bc)(⅓abc)= pls urget
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New questions in Math. please answer these question now itself its urgent please · the 10th term of the sequence root3,root21, root27.
Apply the algebra law a ÷ b = a x 1/b = ( 6a-2bc-3/4ab-3c2 ) x ( 3ab-2c3/ 5a-3 b2c-1 ) = ( 6a-2 bc-3 x 3ab-2c3) / ( 4ab-3c2 x 5a-3b2c-1 ) Apply the law of Fractional Exponents and Laws of Exponents (am)(an) = am+n
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