Question

$y(1 - x)dx + x(1 + y)dy = 0$
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Answer 1

Step-by-step explanation:

Here,

y( 1 - x) dx + x ( 1 + y) dy =0

ydx - ydx² + ydx + y²dx = 0

y²dx + 2ydx - ydx² = 0

Answer 2

Step-by-step explanation:

dxy(1 - x + 1 + y) = 0

dxy = 0 or y - x + 2=0 => y - x = -2 => x - y = 2