Question

3a2-b2-c2+2ab-2bc+2ca

Answer 1

3a2-b2-c2+2ab-2bc+2ca

3a²−b²−c²+2ab−2bc+2ac 
=4a²−a²−b²−c²+2ab−2bc+2ac 
=4a²−(a²+b²+c²−2ab+2bc−2ac) 
=(2a)²−(a−b−c)² 
=(2a+a−b−c)(2a−a+b+c) 
=(3a−b−c)(a+b+c)

Answer 2

Answer:

hope this helps you