Question

3ab-2b2+4abc when a=3,b=3 and c=-4

Answer 1

= 3(3)(3) - 2(3)2 + 4(3)(3)(-4)

= 27 - (-156)

= 183

Answer 2

Answer:

$a = 3 \\ b = 3 \\ c = - 4 \\ \\ 3ab - 2 {b}^{2} + 4abc \\ = 3(3)(3) - 2 {(3)}^{2} + 4(3)(3)( - 4) \\ = 27 - (2 \times 9) + ( - 144) \\ = 27 - 18 - 144 \\ = \underline{ \underline{- 135}}$