-(3ab)³ (-7 a³ b²c⁴ )²
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a³ + 3a²b + 3ab²+ b³ - 8 = ( a + b )³ - 2³ = ( a + b - 2 )[(a+b)² + (a+b)2 + 2² ] = ( a + b - 2 ) [ a²+ 2ab+b² +2a + 2b + 4] = ( a + b - 2 ) ( a² + b²+2ab + ...
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