3ac+2bc+3ad+2bd factorise
Answers
Answered by
90
Hi friend!!
Given,
3ac+2bc+3ad+2bd
Rearranging the terms, we get
3ac+3ad+2bc+2bd
=3a(c+d)+2b(c+d)
=(3a+2b)(c+d)
I hope this will help u ;)
Given,
3ac+2bc+3ad+2bd
Rearranging the terms, we get
3ac+3ad+2bc+2bd
=3a(c+d)+2b(c+d)
=(3a+2b)(c+d)
I hope this will help u ;)
DhanyaDA:
^_^
welldone..^_^
Thanks ^_^
well done
Thank you ^_^
hmm
Answered by
37
⭐Hey here is your answer ⭐
___________________________☺️
✔️✔️Factorise...
3ac + 2bc + 3ad + 2bd
Rearrange...
3ac + 3ad + 2bc + 2bd
3a(c + d) + 2b(c + d)
(3a + 2b) (c + d).... Ans.
I HOPE IT WILL HELP YOU ☺️
Thnx for asking ur question ✌️✌️
___________________________☺️
✔️✔️Factorise...
3ac + 2bc + 3ad + 2bd
Rearrange...
3ac + 3ad + 2bc + 2bd
3a(c + d) + 2b(c + d)
(3a + 2b) (c + d).... Ans.
I HOPE IT WILL HELP YOU ☺️
Thnx for asking ur question ✌️✌️
i don't know
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