Question

(3b+2)(5b-4)-(b-5)(3b+2)simplify ​

Answer 1

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Answer 2

Step-by-step explanation:

[ ( 3b + 2 ) ( 5b - 4) ] - [( b - 5) (3b + 2 ) ] = 0

[ 3b( 5b - 4 ) + 2 ( 5b - 4) ] - [ b ( 3b + 2 ) - 5 ( 3b+ 2 ) ] =0

[ 15 b² - 12b + 10b - 8 ] - [ 3 b²+ 2b -15 b - 10 ] = 0

[ 15 b² - 2b - 8 ] - [ 3 b ² - 13 b - 10 ] = 0

15b ² - 2b - 8 - 3b ² + 13b + 10= 0

12b ² +11 b+2 =0

12 b ² + 8b +3b + 2 = 0

4b ( 3b+ 2) + 1 ( 3b+ 2 ) = 0

3b+2 = 0. and. 4b+1 = 0

3 b = - 2 and. 4b = - 1

b= -2/3. and. b = - 1 / 4