√3cot2teta-3= 0 find value of theta
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√3cot 2∅ - 3 = 0
√3 cot 2∅ = 3
cot 2∅ = 3/√3
cot 2∅ = √3
cot 2∅= cot 30
2∅ = 30
∅ = 30/2 => 15°
√3 cot 2∅ = 3
cot 2∅ = 3/√3
cot 2∅ = √3
cot 2∅= cot 30
2∅ = 30
∅ = 30/2 => 15°
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✓3cot2¢ = 3
cot2¢ = ✓3
cot2¢ = cot30°
2¢ = 30°
¢ = 30/2 = 15°
Hope it helps you ^_^
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cot2¢ = ✓3
cot2¢ = cot30°
2¢ = 30°
¢ = 30/2 = 15°
Hope it helps you ^_^
Mark as brainliest
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