3cotA=2 find 2sinA -cosA /2sinA + 3 cosA
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Solution :
Given 3cotA = 2
=> cotA = 2/3 ----( 1 )
Now ,
( 2sinA - cosA )/( 2sinA + 3cosA )
Divide Numerator and denominator
by sinA , we get
= ( 2 - cotA )/( 2 + 3cotA )
= [ 2 - ( 2/3 )]/[ 2 + 3( 2/3 ) ]
= [ 6 - 2 ]/( 6 + 6 )
= 4/12
= 1/3
•••••2019/1
Given 3cotA = 2
=> cotA = 2/3 ----( 1 )
Now ,
( 2sinA - cosA )/( 2sinA + 3cosA )
Divide Numerator and denominator
by sinA , we get
= ( 2 - cotA )/( 2 + 3cotA )
= [ 2 - ( 2/3 )]/[ 2 + 3( 2/3 ) ]
= [ 6 - 2 ]/( 6 + 6 )
= 4/12
= 1/3
•••••2019/1
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