Question

3cotA=2 find 2sinA -cosA /2sinA + 3 cosA

Answer 1

here you go with the solution and answer

Answer 2

Solution :

Given 3cotA = 2

=> cotA = 2/3 ----( 1 )

Now ,

( 2sinA - cosA )/( 2sinA + 3cosA )

Divide Numerator and denominator

by sinA , we get

= ( 2 - cotA )/( 2 + 3cotA )

= [ 2 - ( 2/3 )]/[ 2 + 3( 2/3 ) ]

= [ 6 - 2 ]/( 6 + 6 )

= 4/12

= 1/3

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