Question

3D vector

Find the image of the point p(1,6,3) on the line X/1 =y-1/2 = z-2/3 . ​

Answer 1

Solution

Step-by-step explanation:

Let x/1 = y-1/2 = z-2/3 = L

x= L , y = 2L + 1 and z = 3L +2

•°• P is given (1,6,3)

M = (L,2L+1,3L+2)

As we know direction ratio of foot of perpendicular * BASE is 0

since, 1(L-1)+2(2L-5) +3(3L-1) = 0

L = 1

M = (1,2,3)

Then using midpoint formula.

let p' is point of image (a, b ,c)

then , a+1/2 =1, b+2/2 =2, c+3/2 = 3

a = 1 , b = 2., c= 3

Point of image is (1,2,3)

_________________________________

Hope it helps !;!