Question

3g of h2 reacts with 29g of o2 to give h20. Calculate max amt of h20 that can be formed

Answer 1

Answer:

2 H 2            + 02         ?  2 H2O

2 X 2.01          32 g            2 x (2.01 + 16 ) = 36 .032

4.03 g

 

3 g of H 2 needs  O2  =  32  

                              --------   X 3  = 23 .8 g

                                4.032

 

S0, 29 g 0f Oxygen is in excess, and hydrogen is the limiting reagent.

 

H2O formed =  36.032  x 3    = 26.8 g

                  --------

                      4.032

 

 

O2 left unreacted = 29 - 23.8

                        =  5.2 g

Explanation:

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Answer 2

Answer:

Explanation:

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