Question

5 gm sample of a sulphite salt was dissolved in 200ml solution & 20 ml of this solution required 10 ml of 0.02m acidified permanganate solution. Hence the % by mass of sulphite in the sulphite salt is

Answer 1

$\huge{\mathfrak{\purple{Answer}}}$

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a sulphite salt was dissolved in 20ml solution and 20ml of this ... its given 20 ml of this requires 10 ml of 0.02M acidified ... So we can write 10* 0.02 *5 = 0.5* 1000/E

Answer 2

Answer

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a sulphite salt was dissolved in 20ml solution and 20ml of this ... its given 20 ml of this requires 10 ml of 0.02M acidified ... So we can write 10* 0.02 *5 = 0.5* 1000/E