3g of magnesium combines with 2g of oxygen to produce 5g of magnesium oxide compound. If 6g of magnesium is allowed to react with 20g of oxygen, what mass of magnesium oxide will be produced in the reaction ? Name the law which governs your answer.
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2mg + o2 - - - - > 2mgo
Where 48g of mg combines with 32g of o2 producing 2*(24+16)=2*40=80g mgo
So we can say 3g mg combines with 2g o2 to produce 5g mgo(dividing by 16)
Now if 6 g mg will only react with 4g 02... By the daltons law that reactants combine in proportionate amounts to form compund with exact chemical formula or the law of proportionality... So when 6g mg reacts with 4g o2 it will produce 10g mgo.... And 16 g 02 will remain unreacted in the reaction. Here mg may be termed as a limiting reagent. Hope this helps... Actually i do not rember the exact name of the law.. So u may want to verify it
Where 48g of mg combines with 32g of o2 producing 2*(24+16)=2*40=80g mgo
So we can say 3g mg combines with 2g o2 to produce 5g mgo(dividing by 16)
Now if 6 g mg will only react with 4g 02... By the daltons law that reactants combine in proportionate amounts to form compund with exact chemical formula or the law of proportionality... So when 6g mg reacts with 4g o2 it will produce 10g mgo.... And 16 g 02 will remain unreacted in the reaction. Here mg may be termed as a limiting reagent. Hope this helps... Actually i do not rember the exact name of the law.. So u may want to verify it
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