3H2 +N2---------------->2NH3. according to the following reaction calculate required amount of dihydrogen and dinitrogen to produce 448000 litre of ammonia gas at
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Answer: 224000litre of H2 and N2
Explanation:
2 moles of nh3 need 1mole of n2
⇒448000ltrs need (1÷2)×448000=224000litres of n2
in the same way do h2
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