Math, asked by anudeep305, 7 months ago

3I+2N+F+T+E

3same+1diff-->1×4C1

2same+2same-->1×1

2same+2diff-->1×4C2+1×4C2

all diff-->5C4

Total 4C1+1+4C2+4C2+5C4=22

Answers

Answered by vidyakarlawad16

0

Answer

.......mmmmmm....

mmmmmmmm

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