Question

(3k+2)^2 leaves remainder ___ on dividing by 3.

Answer 1

Answer:

01

Step-by-step explanation:

Clearly, you can expand that as :

${(3k + 2)}^{2} = 3(3 {k}^{2} + 4k + 1) + 1$

$Hoping \: that, \: k \: is \: an \: integer, \\ \\ (3 {k}^{2} + 4k + 1) \: is \: also \: an \: int.$

Hence, by Euclid's Division Lemma, we can say that the remainder is '1'