(3k-4r-2m)square-(3k+4r-2m)square
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Answered by
15
Hi ,
It is given that ,
( 3k - 4r - 2m )² - ( 3k + 4r - 2m )²
*******************************************
We know the algebraic identity:
x² - y² = ( x - y )( x + y )
******************************************
=[3k-4r-2m-(3k+4r-2m)][3k-4r-2m+(3k+4r-2m)]
= [3k-4r-2m-3k-4r+2m ](6k - 4m )
= ( -8r )( 6k - 4m )
= ( - 8 )r [ 2 ( 3k - 2m ) ]
= ( -16 ) ( 3k - 2m )r
I hope this helps you.
: )
It is given that ,
( 3k - 4r - 2m )² - ( 3k + 4r - 2m )²
*******************************************
We know the algebraic identity:
x² - y² = ( x - y )( x + y )
******************************************
=[3k-4r-2m-(3k+4r-2m)][3k-4r-2m+(3k+4r-2m)]
= [3k-4r-2m-3k-4r+2m ](6k - 4m )
= ( -8r )( 6k - 4m )
= ( - 8 )r [ 2 ( 3k - 2m ) ]
= ( -16 ) ( 3k - 2m )r
I hope this helps you.
: )
Answered by
20
Answer:
32rm-48kr
Step-by-step explanation:
a=3k, b=4r, c=2m
formula- (a+b+c)²
= a²+b²+c²+2ab+2bc+2ca
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