Question

3log5 to the base 2+log10 to the base 2-log625 to the base 2

Answer 1

logarithms

formula used:

log a + log b = log ab

nlog x = log x^n

log a - log b= log (a/b)

solution

$3 log_{2}(5) + log_{2}(10) - log_{2}(625)$

$= log_{2}(125) + log_{2}(10) - log_{2}(625)$

$= log_{2}(1250) - log_{2}(625)$

$= log_{2}( \frac{1250}{625} )$

$= log_{2}(2)$

$= 1$

Follow me

mark answer as brainlist

Answer 2

Logarithm

formula used:

$log(a) + log(b) = log(ab)$

$log(a) - log(b) = log( \frac{a}{b} )$

$n log(x) = log(x {}^{n} )$

•solution:

$3 log_{2}(5) + log_{2}(10) - log_{2}(625)$

$= log_{2}(125) + log_{2}(10) - log_{2}(625)$

$= log_{2}(1250) - log_{2}(625)$

$= log_{2}( \frac{1250}{625} )$

$= log_{2}(2)$

$= 1$

i hope it helps you

follow me

mark answer as brainlist