Math, asked by TanishGR8, 1 year ago

(3m^2/3m^2)^m = 1/81, find the value of m​


amitnrw: LHS = 1 RHS = 1/81 Something wrong with Data

Answers

Answered by knjroopa
27

Answer:

6

Step-by-step explanation:

Given If [3^m² ÷ (3^m)² ]^1/m = 81 , then find the value of m.

We need to find the value of m. By using law of exponents a^m / a^n = a^m-n and (a^m)^n = a^mn  

So we have

[3^m^2 / (3^m)^2]^1/m = 81

3^m / 3^2 = 81 by using (a^m)^n = a^mn

3^m – 2 = 3^4

m – 2 = 4

m = 4 + 2

m = 6

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