Question

3m+7n=27 ; 5m+2n=16 ​

Answer 1

Mulitply second equation by 3 and subract first equation from it,

3(3m+2n)-(4m+6n)=3(28)-54

9m+6n-4m-6n=30

5m=30

m=6

Substitute in first equation,

4(6)+6n=54

6n=54-24

6n=30

n=5

Thus m=6 and n=5

Answer 2

Step-by-step explanation:

Ok let's start the solution, let 3m+7n=27..........(1) 5m+2n=16.......(2) Multiply (1) by 5, you wil get 15m+35n=135......(3) Multipl (2) by 3, you will get 15m+6n=48.......(4) Subtract eq.(4) from eq.(3), you will get n=3 Put n=3 in eq. (2), you will get m=2 Hence,m=2 and n=3 Please bro like,follow and mark as brainlist