Question

3M aqueous solution of glucose find the molarity of same solution density of solution = 1g/L3

Answer 1

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Here it is given as 3M aqueous solution of glucose that means 3 mole of glucose in 1 L of solution

And density of the solution is given as 1g L⁻¹

So mass of the solution comes out to be:

Molality is defined as 1 mole of a solute in 1 kg of solvent.

Here it is given as 3M aqueous solution of glucose that means 3 mole of glucose in 1 L of solution

And density of the solution is given as 1g L⁻¹

So mass of the solution comes out to be:

1 g L^{-1}\times 1 L

1 g

So, molality will become:

Molality= \frac{Number of moles of solute}{Mass of solvent in kg}

Molality=\frac{3}{0.001}

So molality comes out to be 3000m