Question

3n^2-11n+10=0 solve by factorisation method​

Answer 1

Answer:

Use the quadratic formula

=

−

±

2

−

4

√

2

n=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

n=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

3

2

−

1

1

+

1

0

=

0

3n^{2}-11n+10=0

3n2−11n+10=0

=

3

a={\color{#c92786}{3}}

a=3

=

−

1

1

b={\color{#e8710a}{-11}}

b=−11

=

1

0

c={\color{#129eaf}{10}}

c=10

=

−

(

−

1

1

)

±

(

−

1

1

)

2

−

4

⋅

3

⋅

1

0

√

2

⋅

3

Answer 2

Answer:

The answer is (3n-5)(3n-6)

Step to Step Explanation:

It is in the attachments below!!

REMEMBER: This is quadratic it doesnt expand like normal factorisation