CBSE BOARD X, asked by poornimayashwanth198, 5 months ago

3of2u+v=7uv
3ofu+2v=11uv

Answers

Answered by loparathod2609
24

Answer:

Clearly, the given equations are not linear equations in the variables u and v but can be reduced to linear equations by appropriate substitution.

If we put u=0 in either of the two equations, we get v=0.

So, u=0,v=0 form a solution of the given system of equations.

To find the other solutions, we assume that u=0,v=0.

Now, u=0,v=0⇒uv=0.

On dividing each one of the given equations by uv, we get

v6+u3=7 (i)

v3+u9=11 (ii)

Taking u1=x and v1=y, the given equations become

3x+6y=7  ..(iii)

9x+3y=11 .(iv)

Multiplying equation (iv) by 2, the given system of equations becomes

3x+6y=7  .(v)

18x+6y=22 .(vi)

Substracting equation (vi) from equation (v), we get

−15x=−15⇒x=1

Putting x=1 in equation (iii), we get

3+6y=7⇒y=64=32

Now, x=1⇒u1

Answered by MasterUpadhyayHill
7

Answer:

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Explanation:

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