3of2u+v=7uv
3ofu+2v=11uv
Answers
Answer:
Clearly, the given equations are not linear equations in the variables u and v but can be reduced to linear equations by appropriate substitution.
If we put u=0 in either of the two equations, we get v=0.
So, u=0,v=0 form a solution of the given system of equations.
To find the other solutions, we assume that u=0,v=0.
Now, u=0,v=0⇒uv=0.
On dividing each one of the given equations by uv, we get
v6+u3=7 (i)
v3+u9=11 (ii)
Taking u1=x and v1=y, the given equations become
3x+6y=7 ..(iii)
9x+3y=11 .(iv)
Multiplying equation (iv) by 2, the given system of equations becomes
3x+6y=7 .(v)
18x+6y=22 .(vi)
Substracting equation (vi) from equation (v), we get
−15x=−15⇒x=1
Putting x=1 in equation (iii), we get
3+6y=7⇒y=64=32
Now, x=1⇒u1
Answer:
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Explanation:
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