Math, asked by harshitha270, 9 months ago

(3p^2+q^2)*(2q^2-3q^2)
multiply ​

Answers

Answered by sagarnirapure914
9

Answer:

Hey mate.....

Here's ur answer :

Your answer is 14(pq)^2 ,,

(3p^2+q^2)*(2q^2-3q^2)

= 6(pq)^2 + 9(pq)^2 + 2(pq)^2 - 3(pq)^2 ,,

= 15(pq)^2 - (pq)^2

= 14(pq)^2 ,,

▶️Hope it helps «««

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