(3p^2+q^2)*(2q^2-3q^2)
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Answer:
Hey mate.....
Here's ur answer :
Your answer is 14(pq)^2 ,,
(3p^2+q^2)*(2q^2-3q^2)
= 6(pq)^2 + 9(pq)^2 + 2(pq)^2 - 3(pq)^2 ,,
= 15(pq)^2 - (pq)^2
= 14(pq)^2 ,,
▶️Hope it helps ✨«««
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