Question

3p 3p+1 write in the form of euclid division lemma

Answer 1

Answer:

let us take, 'x'= 3q , 3q+1, 3q+2

when, x=3q

x2 = (3q) 2

x2 = 9q2

x2 = 3(3q2)

we see that 3q2= m

so we have done the first equation 3m

when , x=3q+1

x2= (3q+1)2

[since, (a+b)2 = a2+2ab+b2]

x2= 9q+6q+1

x2= 3(3q+2q)+1

in this we see that 3q+2q= m

therefore, this satisfy the equation m+1

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Anshita , Student

Member since Feb 04 2015

let us take, 'x'= 3q , 3q+1, 3q+2

when, x=3q

x2 = (3q) 2

x2 = 9q2

x2 = 3(3q2)

we see that 3q2= m

so we have done the first equation 3m

when , x=3q+1

x2= (3q+1)2

[since, (a+b)2 = a2+2ab+b2]

x2= 9q+6q+1

x2= 3(3q+2q)+1

in this we see that 3q+2q= m

therefore, this satisfy the equation m+1

hope it helps you ♥️♥️