(3p^4-4p^3-3p-1) ÷ (p-1)
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Step-by-step explanation:
if p-1=0
p=1
so if p(1)=0 then p-1 is the factor of p(x)
now
p(x)=3p⁴-4p³-3p-1
p(1)=3(1)⁴-4(1)³-3*1-1
= 3-4-3-1
=-5 ≠0
so (p-1) is not factor of p(x)
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