Question

3p² +2P-8
8
factorise​

Answer 1

(3p2 + 2p) - 8

STEP

2

:

Trying to factor by splitting the middle term

2.1 Factoring 3p2+2p-8

The first term is, 3p2 its coefficient is 3 .

The middle term is, +2p its coefficient is 2 .

The last term, "the constant", is -8

Step-1 : Multiply the coefficient of the first term by the constant 3 • -8 = -24

Step-2 : Find two factors of -24 whose sum equals the coefficient of the middle term, which is 2 .

-24 + 1 = -23

-12 + 2 = -10

-8 + 3 = -5

-6 + 4 = -2

-4 + 6 = 2 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -4 and 6

3p2 - 4p + 6p - 8

Step-4 : Add up the first 2 terms, pulling out like factors :

p • (3p-4)

Add up the last 2 terms, pulling out common factors :

2 • (3p-4)

Step-5 : Add up the four terms of step 4 :

(p+2) • (3p-4)

Which is the desired factorization

Final result :

(3p - 4) • (p + 2)

Answer 2

Answer:

3p²+2p-8

=3p²+6p-4p-8

=3p(p+2)-4(p+2)

=(3p-4)(p+2) ans.