(3p3–9p2q-6pq2) /(–3p)
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We divide the given polynomial 3p
3
−9p
2
q−6pq
2
by the monomial −3p as shown below:
−3p
3p
3
−9p
2
q−6pq
2
=
−3p
3p
3
−
−3p
9p
2
q
−
−3p
6pq
2
=−
3p
3p
3
+
3p
9p
2
q
+
3p
6pq
2
=−(
3p
3×p×p×p
)−(
3p
3×3×p×p×q
)+(
3p
2×3×p×q×q
)
=−p
2
+3pq+2q
2
Hence,
−3p
3p
3
−9p
2
q−6pq
2
=2q
2
+3pq−p
2
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