+3q and -4q charges are placed along x axis 1m apart. Where must be +q charge placed so that +q charge will be in equilibrium.
Answers
Solution
- The charge should be placed in proximity to +3Q
Given
Two Charges of magnitude + 3Q and -4Q are placed one meters apart along the positive x - axis
To finD
A charge Q can be placed so that the former would be in equilibrium
For equilibrium,
The net charge of the system should be zero
By symmetry,
The +Q charge should be placed near +3Q so that this would balance out the -4Q charge and the net charge remains the same
The charge +q shouldn't be placed between the charges +3q & -4q as the direction of Force of repulsion by +3q & - 4q will be along the same direction, and there will be a net force.
So we should place the charge +q at some distance from +3q measured towards - X axis, but not between the charges.
Given Distance between the charges is 1m.
( Measured towards -ve X axis) Let the distance from +q to +3q be x
Then, (Measured towards - ve X axis) The distance between +q & - 4q = 1+x
By Coulomb's law,
Force on +q due to +3q is given by,
Force on +q due to - 4q is given by,
For the charge to be in equilibrium
Total force on the charge = 0
Considering positive value
⇒√3 ( 1 + x) = 2x
⇒ √3 = (2 - √3) x
⇒ √3 ( 2 + √3) = x
⇒3 + 2√3 = x ___ (1)
Considering negative value
⇒-√3 ( 1 + x) = 2x
⇒- √3 = (2 + √3) x
⇒ - √3 ( 2 - √3) = x
⇒ 3 - 2√3 = x _____(2)
Since (2) is a negative value, It is ignored.
Therefore, The Charge +q should be placed at a distance 3 + 2√3 from the charge +3q measured in the direction of -ve X axis.