Question

(3r-2k) +(3r+2k)
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Answer 1

Answer:

6r is correct answer

Step-by-step explanation:

3r-2k+3r+2k

3r+3r

6r

Answer 2

${\boxed {\red{correct \: question}}}$

$(3r - 2k {)}^{3} + (3r + 2 {k)}^{3}$

$\huge \underline {\boxed {\green{answer}}}$

$(3r + 2k {)}^{3} + (3r + 2k {)}^{3}$

$= [(3r {)}^{3} - {3 \times (3r {)}^{2} \times (2k)} + {3 \times( 3r) \times (2k {)}^{2} } + {3 \times (3r) \times (2k {)}^{2} } +( 2k {)}^{3} ]$

${(a + b {)}^{3} = {a}^{3} + 3 {a}^{2}b + 3a {b}^{2} + {b}^{3} \: \: and \: \: (a - b {)}^{3} = {a}^{3} - 3 {a}^{2} b + 3 a {b}^{2} - {b}^{3} }$

swipe left ⬆️⬆️

$= 27 {r}^{3} - {3 \times 9 {r}^{2} \times 2k} + {3 \times 3r \times 4 {k}^{2} } - 8 {k}^{3} + 27 {r}^{3} + {3 \times 9 {r}^{2} \times 2k} + {3 \times 3r \times (4k {)}^{2} } + 8 {k}^{3}$

$= 27 {r}^{3} - 54 {r}^{2}k + 36r {k}^{2} - 8 {k}^{3} + 27 {r}^{3} + 54 {r}^{2} k + 36r {k}^{2} + 8 {k}^{3}$

$= 27 {r}^{3} - 54 {r}^{2} k + 36r {k}^{2} - 8 {k}^{3} + 27 {r}^{3} + 54 {r}^{2} k + 36r {k}^{2} + 8 {k}^{3}$

$= 54 {r}^{3} + 72r {k}^{2}$

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