Question

(3r÷7+7÷65)square-(3r÷7-7÷65)square​

Answer 1

Solution :

LHS=

[(3p/7)+(7/6p)]²-[(3p/7)-(7/6p)]²

*********************

We know that ,

(a+b)²-(a-b)² = 4ab

**********************

Here ,

a = 3p/7 , b = 7/6p

Now ,

= 4×(3p/7)(7/6p)

After cancellation, we get

= 12/6

= 2

= RHS

••••

Answer 2

Hope it helped you please mark it as brainliest ✍️✍️✍️