p(x)=x2-x-12 justify your answers
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Hey
Here is your answer,
X^2 - x - 12 = 0
X^2 - 4x + 3x - 12 = 0
X ( x -4) + 3 ( x - 4 ) = 0
(X-4) (x+3)=0
X-4=0
X=4
X+3=0
X=-3
Hope it helps you!
Here is your answer,
X^2 - x - 12 = 0
X^2 - 4x + 3x - 12 = 0
X ( x -4) + 3 ( x - 4 ) = 0
(X-4) (x+3)=0
X-4=0
X=4
X+3=0
X=-3
Hope it helps you!
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