Question

3rd term 43
6fh term 76
write the first five term​

Answer 1

Step-by-step explanation:

a+2d=43

a+5d=76

Subtracting both,

-3d=-33

d=11

so we can take out a as well

a+22=43

a=21

first term =21

second is 32

third is 43

fourth is 54

fifth is 65

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Answer 2

Answer:

21, 32 , 43 , 54 and 65.

Step-by-step explanation:

 nth term of APs is defined by a + ( n - 1 )d, where a is the first term and d is the common difference.

Let the first term of this AP be a and common difference be d.

      3rd term = 43

  ⇒ a + 2d = 43  

  ⇒ a = 43 - 2d           ...( 1 )

     6th term = 76

  ⇒ a + 5d = 76

  ⇒ 43 - 2d + 5d = 76        {from (1)}

  ⇒ 3d = 76 - 43

  ⇒ 3d = 33

  ⇒ d = 33/3 = 11

Hence,  

    a = 43 - 2d

       = 43 - 2( 11 ) = 43 - 22

       = 21

Hence,

first term = a = 21

2nd = 21 + 11 = 32

3rd = 21 + 22 = 43

4th = 21 + 33 = 54

5th = 21 + 44 = 65