3root18 as rational or irrational
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1
irrational number is the ans
sonupriyasamal:
Irrational no.
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3
3√18 = 3√(9×2)
= 3 × 3√2
= 9√2
9√2 is irrational.
Therefore, 3√18 is irrational.
Proof :
Let 9√2 be a rational number.
A rational number can be written in the form of p/q where p,q are integers and q ≠ 0
9√2 = p/q
√2 = p/9q
p,q are integers then p/9q is a rational number.
Then √2 must also be a rational number.
But this contradicts the fact that √2 is an irrational number.
So,our supposition is false.
Therefore, 9√2 is irrational number.
= 3 × 3√2
= 9√2
9√2 is irrational.
Therefore, 3√18 is irrational.
Proof :
Let 9√2 be a rational number.
A rational number can be written in the form of p/q where p,q are integers and q ≠ 0
9√2 = p/q
√2 = p/9q
p,q are integers then p/9q is a rational number.
Then √2 must also be a rational number.
But this contradicts the fact that √2 is an irrational number.
So,our supposition is false.
Therefore, 9√2 is irrational number.
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