Question

3root4^2x+1/2=1/32 find x

Answer 1

$3 \times \sqrt{ {4}^{2x} } + \frac{1}{2} = \frac{1}{32}$
$3 \times {4}^{ \frac{2x}{2} } + \frac{1}{2} = \frac{1}{32}$
$3 \times {4}^{x} + \frac{1}{2} = \frac{1}{32}$
$3 \times {4}^{x} = \frac{1}{32} - \frac{1}{2}$
$3 \times {4}^{x} = \frac{1 - 16}{32}$
$3 \times {4}^{x} = \frac{ - 15}{2}$
${4}^{x} = \frac{ - 15}{2 \times 3}$
${4}^{x} = \frac{ - 5}{2}$
${2}^{2x} \times 2 = - 5$
${2}^{2x + 1} = - 5$
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