Question

3root45-root125+root200-root50

Answer 1

Given, 3 root 45 - root 125 + root 200 - root 50.

          = 3 * 3  root 5 - 5 root 5 + 10 root 2 - 5 root 2

          = root 5( 9 - 5) + root 2(10 - 5)

         = 4 root 5 + 5 root 2


Hope this helps!

Answer 2

3√45-√125+√200-√50
=(3×√3×√3×√5) -(√5×√5×√5) +(√2×√10×√10) -(√2×√5×√5)
=9√5 -5√5 +10√2 -5√2
=4√5+5√2
=16.01