Question

3sin(2x) - 2 sin(x) = 0

I’m not sure where to start. please help! (trigonometry)

Answer 1

Answer:

3 sin(2x) - 2 sin x= 0

Now,

sin(2x) = 2 sin x cos x

So,

3(2sinxcosx) - 2sinx = 0

or,

2sinx (3cosx - 1) = 0

which implies that

either sin x = 0

for which x = nπ for some integer n

or,

cos x = 1/3

or,

x = 2kπ + cos^-(1/3)

for some integer k

Hope this helps you !

Answer 2

Answer:

lhs

3sin(2x)-2sin(x)=0

2x × x (3sin - 2sin )=0

2x^2(sin)=0

2sin^2x=0

sin^2x=0

2

sin^2x=0

sinx=under root 0

sinx=0

x= 0

sin

x=0

lhs=rhs