Question

[ 3sin (4B+10) + 2 cos(2B+20)] ÷ [2 cos 3B - sin(2B-10)] when B = 20°​

Answer 1

Answer:

Correct option is

A

3

2cos3B−sin(2B−10

∘

)

3sin3B+2cos(2B+5

∘

)

; when B = 20

∘

when, B=20

∘

2cos60

∘

−sin(30

∘

)

3sin60

∘

+2cos(45

∘

)

=

2(

2

1

)−(

2

1

)

3(

2

3

)+2(

2

1

)

=

(

2

2

)−(

2

1

)

(

2

3

3

)+(2

2

2

)

=3

3

+2

2