Question

3sin 58/cos32 - 2sec17/cosec73 + 2sin^2 45

Answer 1

Answer:

1

2(sin32cos58)−3(tan15tan60tan75cos38 cosec52)

2(sin32sin(90−58))−3(tan15tan60tan75sin(90−38) cosec52)                   ∵sin(90−θ)=cosθ

2(sin32sin32)−3(cot(90−15)tan60tan75sin52 cosec52)                  ∵cot(90−θ)=tanθ

2(sin32sin32)−3(cot75tan60tan75sin52 cosec52)    

2−3(tan601)      ∵sinθ cosec θ=1 a

hope it's helpful

Step-by-step explanation:

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