Question

3SinA+4CosA = BSin(C+A) isme A ka man kya hoga plzz give me solution

Answer 1

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Answer 2

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MATHS

In triangle ABC, we are given that 3sinA+4cosB=6 and 4sinB+3cosA=1. Then the measure of the angle C is.

October 15, 2019

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Avdinesh Priya

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ANSWER

3sinA+4cosB=6....(i)

4sinB+3cosA=1....(ii)

squaring and adding (i) and (ii)

(9sin

2

A+16cos

2

B+24sinAcosB)+(16sin

2

B+9cos

2

A+24sinBcosA)=37

9(sin

2

A+cos

2

A)+16(sin

2

B+cos

2

B)+24(sinAcosB+sinBcosA)=37

25+24sin(A+B)=37

24sin(A+B)=12

sin(A+B)=

24

12

=

2

1

As A+B+C=π

A+B=π−C

sin(π−C)=

2

1

π−C=

6

π

⇒C=

6

5π

=150

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