Question

Find the smallest number which leaves reminder 8 and 12 when devided by 28 and 32​

Answer 1

Answer 28 when divided by 20 remainder is 8. 32 when divided by 20 remainder is 12

Answer 2

Given that the smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. Therefore the required number will be 20 less than the LCM of 28 and 32.

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