Question

√3square+10-8√3 factories​

Answer 1

Answer:

sorry I don't know this answer

Answer 2

Answer:

$\huge{{ \pink{solve = > }}}$

Step-by-step explanation:

Answer:

Explanation:

Given quadratic equation:

$\sqrt{ {3x}^{2} } + 10x - 8 \sqrt{3} = 0$

=> √3x²+12x-2x-8√3=0

Rewriting the terms , we get

=> √3x²+(√3x)(4√3)-2x-2×(4√3)=0

=> √3x(x+4√3)-2(x+4√3)=0

=> (x+4√3)(√3x-2)=0

=> x+4√3=0 Or √3x-2 =0

$\begin{lgathered}\implies x = -4\sqrt{3} \\\: Or \:x = \frac{2}{\sqrt{3}}\end{lgathered} \\ \begin{lgathered}\implies x = -4\sqrt{3} \\\: Or \:x = \frac{2\times\sqrt{3}}{\sqrt{3}\times\sqrt{3}}\end{lgathered} \\ \begin{lgathered}\implies x = -4\sqrt{3} \\\: Or\: x = \frac{2\sqrt{3}}{3}\end{lgathered}$

Therefore,

$\begin{lgathered}x = -4\sqrt{3} \\\: Or\: x = \frac{2\sqrt{3}}{3}\end{lgathered} .$

are roots of given quadratic equation.