Question

3t+1/16-2t-3/7=t+3/8+3t-1/14​

Answer 1

Answer:

3t+1)/16-(2t-3)/7=(t+3)/8+(3t-1)/14

lcm of 16,7,8 and 14 is=112

multiply each term by 112

(3t+1)/16*112-(2t-3)7*112=(t+3)/8*112+(3t-1)/14*112

 (3t+1)*7-(2t-3)16=(t+3)*14+(3t-1)*8

21t+7-32t+48=14t+42+24t-8

21t-32t-14t-24t=42-8-7-48

21t-70t=42-63

-49t=-21

t=21/49

Answer 2

Answer:

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Step-by-step explanation:

given,

(3t + 1)/16 - (2t - 3)/7 = (t+3)/8 + (3t - 1)/14

⇒ 7(3t-1) - 16(2t-3)    =  14(t+3) +8(3t-1)

    16 × 7                            14 × 8

⇒21t + 7 -32 +48       = 14t +42+ 24t -8

       112                                112

⇒21t - 32t -14t -24t  = -48-7+42-8

⇒ -49 t = - 21

⇒t = 21/ 49

⇒ t = 3/7