3t-2/4-2t+3/3=2/3-t then 't' is
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Answer:T=2
Step-by-step explanation:
I soled it look
Given(3t−2)/4−(2t+3)/3=2/3−t
Now by taking L.C.M for 4 and 3 is 12
(3(3t−2)−4(2t+3))/12=2/3−t
By transposing the above equation we can write as
(9t−6−8t−12)/12=2/3−t
t+12t=8+18
Again by transposing
t = 26/13
t = 2
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