The height of a parallelogram is one third of its base. If the area of the parallelogram is 192 cm², find its height and base.
Answers
Step-by-step explanation:
Given
Area of parallelogram = 192cm2
The height of a parallelogram is one-third of its base
So
Let the base be x cm.
Height = 1/3x cm.
Area of Parallelogram = Base X Height
Base × Height = 192
x × 1/3x = 192
= 1/3 x2 = 192
= x2 = 192 × 3
= x2 = 576
x = √576
x = 24cm
Base = x = 24cm.
And Height = 1/3x = 1/3 × 24
= Height = 8 cm
Base= 24cm and height = 8cm
- Height of the parallelogram = 8 cm.
- Base of the parallelogram = 24 cm.
Given :–
- Area of the parallelogram = 192 cm²
- Height of the parallelogram is one third of its base.
To Find :–
- Height of the parallelogram.
- Base of the parallelogram.
Solution :–
Let,
• The height of the parallelogram be x.
• The base of the parallelogram be y.
According to the question,
Height of the parallelogram is one third of its base.
–––(1)
We know that,
Area of the parallelogram = Base × Height
Base × Height = 192 cm²
So,
- y = base = 24 cm.
Now, we have to find the height of the parallelogram.
Given that,
Height =
Now, substitute the value of base in eqn. (1),
Hence,
The height of the parallelogram (x) is 8 cm.
The base of the parallelogram (y) is 24 cm.
Check :–
Area of the parallelogram = Base × Height
Base × Height = 192 cm²
- Base = 24 cm.
- Height = 8 cm.
Since, the area of the parallelogram 192 cm is equal to the given value of the area.
So, the base and the height of the parallelogram is 24 cm and 8 cm is correct.