Question

(3tan45) (4sin60) - (2cos30) (3sin30)

Answer 1

This is ur answer. Hope u got it

Answer 2

$\huge {\underline {\mathcal{Question}}}$

(3tan45) (4sin60) - (2cos30) (3sin30)

$\huge {\underline {\mathcal{Solution}}}$

As we know that ...

$\tan(45) = 1$

$\sin(60) = \frac{ \sqrt{3} }{2}$

$\cos(30) = \frac{ \sqrt{3} }{2}$

$\sin(30) = \frac{1}{2}$

By putting all this values , ...

(3tan45) (4sin60) - (2cos30) (3sin30)

$= (3 \times 1)(4 \times \frac{ \sqrt{3} }{2} ) - (2 \times \frac{ \sqrt{3} }{2} )(3 \times \frac{1}{2} )$

$= (3)(2 \sqrt{3} ) - ( \sqrt{3} )( \frac{3}{2} )$

$= 6 \sqrt{3} - \frac{3}{2} \sqrt{3}$

$= 3 \sqrt{3} (2 - \frac{1}{2} )$

$= 3 \sqrt{3} \times \frac{3}{2}$

$= \frac{9 \sqrt{3} }{2}$